Part 1: A Deep Dive into Rust and C Memory Interoperability
23 comments
·August 4, 2025ryanf
This article looked interesting, but I bounced off it because the author appears to have made heavy use of an LLM to generate the text. How can I trust that the content is worth reading if a person didn't care enough to write it themselves?
TechDebtDevin
Do you see Emojis in tables/code now and assume the person is using an llm? I dont really see it.
ryanf
Maybe I'm too paranoid! If it's not LLM then I don't think it's a very well-organized post though.
In addition to the emoji, things that jumped out at me were the pervasive use of bullet lists with bold labels and some specific text choices like
> Note: The bash scripts in tools/ dynamically generate Rust code for specialized analysis. This keeps the main codebase clean while allowing complex experiments.
But I did just edit my post to walk it back slightly.
phkahler
Something I'd like to know for mixing Rust and C. I know it's possible to access a struct from both C and Rust code and have seen examples. But those all use accessor functions on the Rust side rather than accessing the members directly. Is it possible to define a structure in one of the languages and then via some wrapper or definitions be able to access it idiomatically in the other language? Can you point to some blog or documentation explaining how?
GrantMoyer
Rust bindgen[1] will automatically generate native Rust stucts (and unions) from C headers where possible. Note that c_int, c_char, etc. are just aliases for the corresponding native Rust types.
However, not all C constructs have idomatic Rust equivalents. For example, bitfields don't exist in Rust, and unlike Rust enums, C enums can have any value of the underlying type. And for ABI reasons, it's very commom in C APIs to use a pointer to an opaque type paired with what are effectively accessor function and methods, so mapping them to accessors and methods on a "Handle" type in Rust often is the most idomatic Rust representation of the C interface.
Arnavion
I don't know what examples you've been seeing. The interop structs are just regular Rust structs with the `#[repr(C)]` attribute applied to them, to ensure that the Rust compiler lays the struct out exactly as the C compiler for that target ABI would. Rust code can access their fields just fine. There's no strict need for accessor functions.
stouset
And vice versa. Rust code and C code can both operate on each other’s structs natively.
`#[repr(C)]` instructs the compiler to lay the struct out exactly according to C’s rules: order, alignment, padding, size, etc. Without this, the compiler is allowed a lot more freedom when laying out a struct.
eatonphil
One of the areas I wonder about this a lot is when integrating Rust code into Postgres which has its own allocator system. Mostly right now when we need to have complex data structures (non-Postgres data structures) that must live outside of the lexical scope we put them somewhere global and return a handle to the C code to reference the object. But with the upcoming support for passing an allocator to any data structure (in the Rust standard library anyway) I think this gets a lot easier?
tialaramex
For me the most interesting thing in Allocator is that it's allowed to say OK, you wanted 185 bytes but I only have a 256 byte allocation here, so, here is 256 bytes.
This means that e.g. a growable container type doesn't have to guess that your allocator probably loves powers of 2 and so it should try growing to 256 bytes not 185 bytes, it can ask for 185 bytes, get 256 and then pass that on to the user. Significant performance is left on the table when everybody is guessing and can't pass on what they know due to ABI limitations.
Rust containers such as Vec are already prepared to do this - for example Vec::reserve_exact does not promise you're getting exactly the capacity you asked for, it won't do the exponential growth trick because (unlike Vec::reserve) you've promised you don't want that, but it would be able to take advantage of a larger capacity provided by the allocator.
Arnavion
>But with the upcoming support for passing an allocator to any data structure (in the Rust standard library anyway) I think this gets a lot easier?
Yes and no. Even within libstd, some things require A=GlobalAlloc, eg `std::io::Read::read_to_end(&mut Vec<u8>)` will only accept Vec<u8, GlobalAlloc>. It cannot be changed to work with Vec<u8, A> because that change would make it not dyn-compatible (nee "object-safe").
And as you said it will cut you off from much of the third-party crates ecosystem that also assumes A=GlobalAlloc.
But if the subset of libstd you need supports A=!GlobalAlloc then yes it's helpful.
steveklabnik
I’m not sure what those two things have to do with each other, though I did just wake up. The only thing the new allocator stuff would give you is the ability to allocate a standard library data structure with the Postgres allocator. Scoping and handles and such wouldn’t change, and using your own data structures wouldn’t change.
It’s also very possible I’m missing something!
eatonphil
> The only thing the new allocator stuff would give you is the ability to allocate a standard library data structure with the Postgres allocator.
Yeah no this is basically all I'm saying. I'm excited for this.
tracker1
Interesting read... and definitely good to know base of knowledge especially if you're working in transitional or mixed codebases.
sesm
Section named "The Interview Question That Started Everything" doesn't contain the interview question.
hyperbrainer
That's the first thing on the page.
> Interviewer: “What happens if you allocate memory with C’s malloc and try to free it with Rust’s dealloc, if you get a pointer to the memory from C?”
> Me: “If we do it via FFI then there’s a possibility the program may continue working (because the underlying structs share the same memory layout? right? …right?)”
7e
Allocating memory with C and freeing it with Rust is silly. If you want to free a C-allocated pointer in Rust, just have Rust call back in to C. Expecting that allocators work identically in both runtimes is unreasonable and borderline insane. Heck, I wouldn't expect allocators to work the same even across releases of libc from the same vendor (or across releases of Rust's std).
benmmurphy
usually when interfacing with a library written in c the library will export functions for object destruction. it makes sense for that to be part of the interface instead of using the system allocator because it also gives the library freedom to do extra work during object destruction. if you have simple objects then its possible to just use the system allocator, but if you have graphs or trees of objects then its necessary to have a custom destroy function and there is always some risk in the future you might be forced to need to allocate more complex data structures that require multiple allocations.
rectang
I don't agree with your contemptuous framing. It's incorrect, and per the post's author, "dangerous" — but depending on your background it's not "silly" or "borderline insane". It's just naive, and writing a slab allocator as an exercise or making honest explorations like in this blog post will help cure the naivete.
Arnavion
The article is about how and why mixing allocators fails, not if it fails or how to fix the problem.
potatogotato
PART 2 WHEN?
(also pls sign my tits! <3)
potatogotato
PART 2 WHEN
The reason you are not seeing crashes when allocating with Rust and freeing with C (or vice versa) is that by default Rust also uses the libc allocator.
https://stdrs.dev/nightly/x86_64-unknown-linux-gnu/src/std/s...