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Binary Wordle

Binary Wordle

139 comments

·June 4, 2025

AmsterErdo

I think I don't get it... since it's binary, it can always be guessed in two attempts?

gamerDude

It took me 10 tries...

cookie_monsta

The classics are classics for a reason

financypants

That's pretty good, considering they give you 110 tries

williamdclt

I _think_ it's humorous!

awwaiid

Yes. You can still try to get it in one attempt.

brookst

Odds in one attempt: 1 in 32

Odds in two attempts: 1 in 1

dskloet

Your odds add up to more than 1.

xandrius

Ooops:

You won!

You guessed 01111 in 4 attempts!

null

[deleted]

sashank_1509

I’m glad I figured that out after my first attempt. I feel smart lol.

igitur

I'm waiting for the NY Times to sue this one too.[1]

[1] https://apnews.com/article/new-york-times-wordle-clones-take...

tylerchr

My wife took one look at this and said “It’s not Wordle if it’s all binary—it’s Digitle.”

layer8

selcuka

5 bits would be a weird size for a word.

flysand7

Knuth's "Art of Programming" had a hypothetical machine with 5-bit words.

layer8

I don’t think the parent’s argument would change if he had made an 8-bit Wordle.

badc0ffee

Baudotle

HPsquared

Reminds me of the idea of analogue cheese - fake cheese. It's analogue cheese until you get some on your fingers, when it becomes digital cheese.

gowld

It's not Wordle because because it's only 5 bits. There are no remotely common 5-bit word systems.

https://en.wikipedia.org/wiki/Word_(computer_architecture)#T...

umvi

Binary is too easy, but hex can be tricky. I made a hex-based wordle puzzle for my programming game where you have to guess an 8-digit hex string in as few as 6-12 guesses using wordle mechanics... called the level "dwordle" :)

(video from like 3 years ago: https://www.reddit.com/r/Unity2D/comments/sq4anb/i_added_a_w...)

charly187

Someone should make a base-26 version! It would probably be super popular!

Aissen

I love that someone went all the way to write and publish this joke. Keep hacking!

gowld

1 minute and 2 1-sentence prompts: https://g.co/gemini/share/a14f3f1b1c1c

Gemini self-improved version (added the "Hint" and "What could it mean?" features): https://g.co/gemini/share/05c8cce3b2ff

Aissen

Nice, it seems the share links don't show the prompts (or I missed it); could you share them please?

asimovDev

https://horsle.glitch.me reminds me of this

tetris11

quite difficult, there aren't many horse anagrams

wongogue

My trick is to use HORSE as the starting word.

patrakov

Step 1: Guess 00000.

Step 2: Replace all grey cells with 1s.

0xAFFFF

This is obviously improper. The valid strategy for this game unfolds as follows.

Step 1: Guess 11111.

Step 2: Replace all grey cells with 0s.

Thank you for your careful consideration.

nmeofthestate

If you start with 0's you save a small amount of electricity. 1's use up more electricity - any electronic engineer will agree.

justsid

Not to ruin a joke, but does it actually make a difference for SRAM? It’s two inverters in a loop, despite not being the same size they are active components. But I’m also a software guy so I could be totally wrong.

heckelson

And for a second, I was proud that I solved mine in 3 steps...

null

[deleted]

paxys

Step 1: Guess anything

Step 2: Flip all the non green cells.

underlines

afaik, guessing anything not 00000 or 11111 at first step will lead to an optimum strategy of 3 steps. because you introduce possible "right digit at wrong place" as a third state.

guessing 00000 or 11111 removes that third state and leaves you with simple substitution of wrong cells, which leads to an optimal 2 step strategy.

but obviously the shortest strategy is just guessing it right on the first try :D lol

paxys

It doesn't matter.

Right digit at the wrong place = wrong digit = you should flip it.

This puzzle won't take more than 2 guesses no matter what you input the first time.

Jtsummers

It's still two steps. You only ever need to flip wrong digits.

jesse__

I think it's actually possible to win on the second guess with any initial input. Or at least I did it a handful of times..

vikingerik

This should be correct. For any cell that isn't green after your first guess, there's only one other possibility for its value.

dskloet

It's not guaranteed you will always win in 2 steps because occasionally you will win in 1 step.

Supermancho

Isn't 1 within the bounds of 2?

selcuka

Yes. Yellow and grey mean exactly the same thing in this game: Flip it.

IAmBroom

Hoping that you are being sarcastic...

stavros

gus_massa

I solved it in one attempt! https://imgur.com/a/jklkc7F

Spoiler alert: There is a nice video by Captain Disillusion https://www.youtube.com/watch?v=ou7KSmfC3lA (the relevant part is https://www.youtube.com/watch?v=ou7KSmfC3lA&t=275s )

petra303

Yea, you don’t need more than two chances.

bbassett

and now we know how raid parity works

topato

This is some how the most concise description of parity ever

a3w

I think I saw a two.

There is no such thing as a two, Bender!

freedomben

There should be a 1 in 1,000 chance that a two slips in to one of the puzzles, and then can't be reproduced.

Sesse__

I intended this strategy, but 00000 happened to be correct, so I didn't even need a step 2.

zck

I also made some number-based wordle-variants, which I call "numberdle". I found that it was hard to come up with good ways of guessing because wordle has the restriction that most combinations are invalid. You won't ever have to guess xwqqf, because that's not an English word. And more importantly, guessing some letters gives you information about the other letters. If you find out three letters, and have the target as _a_ts, you can use that to figure out the other two letters.

But if you need to guess a number, and you know it's _5_34, having three correct digits don't help you figure it out.

So I made some variants where guessed values do help you figure out the correct answer.

In rationerdle (https://zck.org/numberdle/?variant=rationerdle), you have to guess a rational number x/y, where both x and y are between 1 and 99, inclusive. It displays the rational number you actually guessed, and whether x and y separately are too high or too low.

In factordle (https://zck.org/numberdle/?variant=factordle), the player has to guess the factors of a target number.

In formuladle (https://zck.org/numberdle/?variant=formuladle), there is a graphed straight line, and the player has to guess the mx+b formula that graphs that line.

I would like to make more, but didn't have any other great ideas when I ran out of interest.

abotsis

Yea, it’s too easy. Maybe if it were a “guess the number” but in binary? Hints are just “too high” or “too low”?

…though now that I’m playing it in my head that’s too easy too. (Start at MSB and shift right if too high and add bits if too low)…

Maybe if you reduced the number of guesses to 5 that’d add enough chance to make it fun?

TheDong

It's not supposed to be fun or hard, it's supposed to be funny. It's absurdist humor.

James-Livesey

If anyone's in need of a hexadecimal version... https://jamesl.me/hexle/

I similarly made a binary one before this version, but unsurprisingly, a lot of people said they found it too easy!

charlie-83

The hint actually makes it harder since I was required to guess a 0 and a F each time

NoSalt

I did it in two attempts ... read it and weep, suckas!

NotAnOtter

This delivers on the title but I wonder if you could tweak it to make it an actual game without wildly overcomplicating it.

Maybe make the string much longer, like 10 bits, and the game only matches on substrings longer than 3. 000...000 would generally return no matches.

That's still probably solvable with superpermutations but wordle is "solvable" with a dictionary, so don't let perfect be the enemy of "better than 2 guess bordle"